I never said 100% but at least you are starting to get a grasp on force vectors. The force of expulsion came out on the front right side, therefore Kennedy's reaction was in the opposite direction, back and to the left. It's simple physics even a child could understand




JohnM
I never said 100% There's a misunderstanding here.
I posted that the high contrasted image of the head shot in z313 that you posted "100% does NOT show the "expulsion of matter out the front".
I am over-emphasising that this image does not show matter being expelled from the front. The "100%" is part of that over-emphasis.
You seem to be thinking that I posted that the image does not show the expulsion of 100% of matter out the front.
It just seems like a straight forward misunderstanding.
"...but at least you are starting to get a grasp on force vectors."Hmm...maybe you can help me out.
In the image below the red lines are the two trails of matter that have been ejected from JFK's head.
We'll imagine that they are continuous columns of matter that are connected to the head (which they clearly aren't) and that way we can consider them to be "jets"
And we'll imagine that they are of equal force (which they clearly aren't) as this will allow us to more easily figure out the position of the resultant vector.
So these two red lines are "vector a" (on the right) and "vector b" (on the right)
The yellow line passes directly through the top of JFK's head an shows the orientation of his head at z313.
The blue line is the resultant vector.
Even in this diagram, with everything in the favour of your theory, we can see that the resultant vector is still to the left of JFK's centre-line.
This means that any "equal and opposite force" acting down this resultant vector would still be pushing JFK's head downwards and forwards.

On every single level the "Jet Effect" fails.
Even a child can see that.